How do you solve the equation #3sqrt(x) = x- 4#?

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Answer 1 · 2016-11-27T22:29:00

#x= 16#

#3sqrt(x) = x - 4#

#(3sqrt(x))^2 = (x- 4)^2#

#9(x) = x^2 - 8x+ 16#

#0 = x^2 - 17x + 16#

#0 = (x - 16)(x - 1)#

#x = 16 and 1#

Check:

#3sqrt(16) + 3 =^? 16 - 1#

#3(4) + 3 = 15" "color(green)(√)#

#3sqrt(1) + 3 =^? 1 - 1#

#3 + 3 != 0" "color(red)(xx)#

Hopefully this helps!