Question

How do you evaluate square root of 9x^4 + square root of 16x?

Answer 1

`sqrt(9x^4) + sqrt(16x)`
`3x^2 + 4sqrt(x)`

Explanation:

`sqrt (9x^4)` is a perfect square which is `sqrt((3x^2)(3x^2))` and the `sqrt(16x)` is equal to `sqrt((4^2)(x))`. Therefore the answer is `3x^2` + `4sqrt(x)`.