How do you factor #14x^2 + 29x - 15#?

1 Answer
May 29, 2015

If #14x^2+29x-15#
#=(ax+b)(cx-d) color(white)("XXXXX")#we know there needs to be a 'minus' on the #d# because of the 'minus' on #15#

then we are looking for

  • factors #a and c# of #14#, and
  • factors #b and d# of #15#
    such that #bc-ad = 29#

Fortunately there are not a lot of factor pairs for #14 and 15#
so we can quickly come up with
#(2x+5)(7x-3)#