How do you factor #x^2 +3x - 18 = 0#?

1 Answer
May 23, 2015

# x^2 + 3x -18#

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like #ax^2 + bx + c#, we need to think of 2 numbers such that:

#N_1*N_2 = a*c = 1*(-18) = -18#
and,
#N_1 +N_2 = b = 3#

After trying out a few numbers we get #N_1 = 6# and #N_2 =-3#
#6*(-3) = -18# and #6+(-3)= 3#

# x^2 + 3x -18 = x^2 + 6x - 3x -18#

# x(x+6) -3(x+6)#

#color(green)((x-3)color(red)((x + 6)# is the factorised form.