How do you solve #10A=60-2A#?

1 Answer
Dec 23, 2016

#A = 5#

Explanation:

First, isolate the #A# terms on the left side of the equation and the constants on the right side of the equation while keeping the equation balanced:

#10A + color(red)(2A) = 60 - 2A + color(red)(2A)#

#(10 + 2)A = 60 - 0#

#12A = 60#

Now we can solve for #A# by dividing each side of the equation by #color(red)(12)# which will also keep the equation balanced:

#(12A)/color(red)(12) = 60/color(red)(12)#

#(color(red)(cancel(color(black)(12)))A)/cancel(color(red)(12)) = 5#

#A = 5#