How do you solve #11.1c-2.4=-8.3c+6.4#?

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Answer 1 · 2016-08-09T16:27:31

Exact value#->c=44/97#

App. value #->0.454# to 3 decimal places

Lets get rid of the decimals!

Multiply everything by 10

#10(11.1c-2.4)=10(-8.3c+6.4)#

#111c-24=-83c+64#

Collecting like terms

#111c+83c=64+24#

#=>194c=88#

Divide both sides by 194

#=>c=88/194=44/97~~0.454#