How do you solve #2(3x+4)-3=5+6x#?

1 Answer
Nov 29, 2016

#x# can have have value.

Explanation:

Multiply out he bracket first

#2(3x+4)-3 = 5+6x#

#6x+8-3 = 5+6x#

#6x+5 = 6x+5" "larr# notice the two sides are identical

#6x-6x = 5-5#

#0=0#

This is a true statement, but there is no #x# left to solve for.
This is an indication that you are working with an identity which means it is an equation which will be true for any value of #x#.

There are infinitely many solutions.