How do you solve #-2(w+1)+w=7-4w#?

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Answer 1 · 2018-03-18T21:16:01

#w=3#

Let's start by distributing the #-2# on the left to the terms in parenthesis. We get:

#-2w-2+w=7-4w#

Next, we can combine left terms on the left to get:

#-2-w=7-4w#

We can add #4w# to both sides to get:

#-2+3w=7#

Adding #2# to both sides, we get:

#3w=9#

And finally, we can divide both sides by #3# to get

#w=3#