How do you solve #2(x=1)=3x-3#?

1 Answer
Mar 25, 2015

Solve: #2(x-1)=3x-3#

Remove the parentheses (by distributing the multiplication). Then Collect all terms involving the unknown (#x#) on one side and all other terms on the other side. Finish by dividing both sides by the coefficient of #x# (the number in front of #x#.

It looks like this:

#2(x-1)=3x-3#
#2x-2=3x-3#

Method 1, collect #x#-terms on the left.
#2x-2=3x-3#
(add #2# and subtract #3x# from both sides. Then divide)

#2x-3x=-3+2#
#-x=-1#

#(-x)/(-1)=(-1)/(-1)#

#x=1#

(There are other ways of convincing yourself that ix #-x=-1# is to be true, then we'll need to have #x=1#)

Method 2, avoid negatives in front of #x#
#2x-2=3x-3#

(add #3# and subtract #2x# on both sides)

#-2+3=3x-2x#
#1=x#
#x=1#