How do you solve #3p-1=5(p-1)-2(7-2p)#?

1 Answer
Mar 14, 2017

See answer in solution below.

Explanation:

To start, it's a good idea to being by distributing the numbers outside of both of the parentheses to get individual terms

#3p - 1 = 5p - 5 -14 + 4p#

Then we combine like terms on both sides to get

#3p - 1 = 9p - 19#

Then we want to get the terms with #p# on one side and all the terms without #p# on the other side. It doesn't matter which one goes where but I prefer working with a positive coefficient in front of my variable so let's subtract #3p# from both sides and then add #19# to both sides to give us

#18 = 6p#

Then to get #p# alone we divide both sides by six which gives us

#3 = p#

And that is the final answer.