How do you solve #3x + 11= 19- x#?

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Answer 1 · 2018-04-23T19:31:15

#x=2#

Get the #x's# to one side:

#3x+11+x=19-cancelx+cancelx#

Collect like terms:

#4x+11=19#

Get #x# on its own:

#4x+cancel11-cancel11=19-11#

#-> 4x=8#

Divide to solve for #x#

#x=8/4 -> 2#

#x=2#

Always put in this value to check:

#(3 xx 2)+11=19-2#

#6+11=17#

#17=17# which is correct.