How do you solve #4(y-2/4)=9(y+1/3) #?
1 Answer
Dec 20, 2015
Explanation:
According to BEDMAS, work on the brackets first. Reduce
#4(y-1/2)=9(y+1/3)#
Make the bracketed terms have the same denominator.
#4((2y)/2-1/2)=9((3y)/3+1/3)#
Subtract the bracketed terms.
#4((2y-1)/2)=9((3y+1)/3)#
Reduce the fractions by cancelling.
#color(red)cancelcolor(black)4^2((2y-1)/color(red)cancelcolor(black)2)=color(blue)cancelcolor(black)9^3((3y+1)/color(blue)cancelcolor(black)3)#
Rewrite the equation.
#2(2y-1)=3(3y+1)#
Multiply.
#4y-2=9y+3#
Isolate for
#4y-9y=3+2#
Solve.
#-5y=5#
#y=-1#