How do you solve #4c-4<8c-16<6c-6#?

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Answer 1 · 2018-06-28T19:37:06

#3 < c < 5#

#4c - 4 < 8c - 16 < 6c - 6#

separate into two inequalities:

#4c - 4 < 8c - 16#
#8c - 16 < 6c - 6#

solving #4c - 4 < 8c - 16#:

#-4 < 4c - 16#

#12 < 4c#

#3 < c#

solving #8c - 16 < 6c - 6#:

#8c < 6c + 10#

#2c < 10#

#c < 5#

now we have #3 < c# and #c < 5#

giving #3 < c < 5#.