How do you solve #-4x - 2= - 2+ 8x#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Nam D. Jan 26, 2018 #x=0# Explanation: Isolate #x# on to one side. #-4x-2=-2+8x# I can add #4x# to both sides to eliminate #-4x# on the #LHS#. #:.cancel(-4x)-2+cancel(4x)=-2+8x+4x# #-2=12x-2# Adding #2# to both sides eliminates both #2#'s. #cancel(-2)+cancel(2)=12x-cancel(2)+cancel(2)# #12x=0# #x=0# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1300 views around the world You can reuse this answer Creative Commons License