How do you solve #4x + 7 = 6x - 1#?

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Answer 1 · 2018-05-07T03:21:30

#x=4#.

Start by bringing all of the variables onto one side of the equation. In this case, Let's subtract 4x from both sides to give us:

#7=6x-4x-1#

Perform indicated steps as allowed (subtract #4x# from #6x#, giving us #2x#). So:

#7=2x-1#

Let's get all of the non-variables onto one side of the equation, the simplest way to do this is to add #1# to both sides:

#7+1 =2x#

Perform indicated steps as allowed (add #7# plus #1#, giving us #8#). Now, we are looking at

#8=2x#

Let's divide both sides by the coefficient of #x# (which is #2#), and that gives us:

#4=x#

Because the equals sign is transitive, we can also state this as

#x=4#