How do you solve #5/6(12p+4)=-13p+4#?

1 Answer
Jan 26, 2017

See the entire solution process below:

Explanation:

First, multiply both sides of the equation by #color(red)(6)# to eliminate the fraction and keep the equation balanced:

#color(red)(6) xx 5/6(12p + 4) = color(red)(6)(-13p + 4)#

#cancel(color(red)(6)) xx 5/color(red)(cancel(color(black)(6)))(12p + 4) = color(red)(6)(-13p + 4)#

#5(12p + 4) = color(red)(6)(-13p + 4)#

#60p + 20 = -78p + 24#

Next add #color(red)(78p)# and subtract #color(blue)(20)# from each side of the equation to isolate the #p# terms while keeping the equation balanced:

#60p + 20 + color(red)(78p) - color(blue)(20) = -78p + 24 + color(red)(78p) - color(blue)(20)#

#60p + color(red)(78p) + 20 - color(blue)(20) = -78p + color(red)(78p) + 24 - color(blue)(20)#

#138p + 0 = 0 + 4#

#138p = 4#

Now, divide each side of the equation by #color(red)(138)# to solve for #p# while keeping the equation balanced:

#(138p)/color(red)(138) = 4/color(red)(138)#

#(color(red)(cancel(color(black)(138)))p)/cancel(color(red)(138)) = 2/69#

#p = 2/69#