How do you solve #-2<=x-7<=11#?
1 Answer
Explanation:
The first thing to do here is get
#-2 + 7 <= x - color(red)(cancel(color(black)(7))) <= 11 + 7#
#color(white)(aaaaa)5 <= color(white)(aa)xcolor(white)(aa) <= 18#
You now know that in order to be part of the solution interval, a value of
#x >= color(white)(1)5 -># the left side of the compound inequality
#x <= 18 -># the right side of the compound inequality
For the first condition, you need
#x in [5, +oo)#
For the second condition, you need
#x in (-oo, 18]#
This means that the solution interval for the compound inequality must have
Thsi is written as
#x in (-oo, 18] nn [5, +oo) implies color(green)(|bar(ul(color(white)(a/a)color(black)( x in [5, 18])color(white)(a/a)|)))#