Question

How do you solve compound inequalities `8 - 4x < -3x + 5` or `x + 8 > 4 + 3x`?

Answer 1

(1) x + 8 > 4 + 3x -> 2x < 8 - 4 -> x < 2

(2) 8 - 4x < -3x + 5 -> 8 - 5 < 4x - 3x -> x > 3
.
The solution set are the 2 open intervals: (-infinity , 2) and (3, +infinity)