How do you solve for x in #2(8-x)=-6#?
1 Answer
Jul 18, 2016
Explanation:
To solve for
#2(8-x) = -6#
#16 - 2x = -6#
Now isolate the variable by getting it by itself on one side. Subtract
#cancel(16-16)-2x = -6-16#
#-2x = -22#
Get rid of the coefficient to identify
#(cancel(-2)x)/(cancel(-2)) = -22/-2#
#x = 11#