How do you solve the equation #5x+12=-3x-4#?
1 Answer
Jan 20, 2017
Explanation:
Collect terms in x on the left side of the equation and numeric values on the right side.
add 3x to both sides.
#5x+3x+12=cancel(-3x)cancel(+3x)-4#
#rArr8x+12=-4# subtract 12 from both sides.
#8xcancel(+12)cancel(-12)=-4-12#
#rArr8x=-16# To solve for x, divide both sides by 8
#(cancel(8) x)/cancel(8)=(-16)/8#
#rArrx=-2#
#color(blue)"As a check"# Substitute this value into the equation and if the left side is equal to the right side for this value then it is the solution.
#"left side "=(5xx-2)+12=-10+12=2#
#"right side "=-(3xx-2)-4==6-4=2#
#rArrx=-2" is the solution"#