How do you solve the equation shown below algebraically: #6(x+1)-3(x-2)=x+4#?

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Answer 1 · 2016-10-26T05:06:25

#x=-4#

#6(x+1)-3(x-2)=x+4#

Open the brackets, multiplying the terms within with the number outside and keeping in mind that two negatives make a positive. Then simplify.

#6x+6-3x+6=x+4#

#3x+12=x+4#

Group all the x terms on the left and the integers on the right, changing values appropriately. Then simplify.

#3x-x=4-12#

#2x=-8#

Divide both sides by #2#.

#x=-4#