How do you solve the equation #x+17=10-3x#?
1 Answer
Jan 22, 2017
Explanation:
Collect terms in x on the left side of the equation and numeric values on the right side.
add 3x to both sides.
#x+3x+17=10cancel(-3x)cancel(+3x)#
#rArr4x+17=10# subtract 17 from both sides.
#4xcancel(+17)cancel(-17)=10-17#
#rArr4x=-7# To solve for x, divide both sides by 4
#(cancel(4) x)/cancel(4)=(-7)/4#
#rArrx=-7/4#
#color(blue)"As a check"# Substitute this value into both sides of the equation and if they are equal for this value then it is the solution.
#"left side "=-7/4+17=-7/4+68/4=61/4#
#"right side "=10-(3xx-7/4)=40/4+21/4=61/4#
#rArrx=-7/4" is the solution"#