What is the solution set of #(h-6)^2=400#?

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Answer 1 · 2018-04-10T01:44:22

26.

You are solving for h here, so you would first square root both sides of the equation to get

h-6=20.

Then you add 6 to both sides to get

h=26.

Answer 2 · 2018-04-10T01:54:01

The two solutions are #h=26# and #h=-14#.

You can square root both sides to cancel the power:

#(h-6)^2=400#

#color(red)sqrt(color(black)((h-6)^2))=color(red)sqrtcolor(black)400#

#h-6=color(red)sqrtcolor(black)400#

#h-6=+-20#

Solve each equation separately for two solutions:

#h-6=20#

#h=26#

And:

#h-6=-20#

#h=-14#

Those are the two solutions. Hope this helped!